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Captain Morgan
01-22-2011, 10:46 AM
A friend on facebook posted this problem from her son's 6th grade math. I'm clearly an idiot, cause I can't figure it out.

If y*=3y-1, then what is 3*+5?

Seems to me that you have to solve for the y and also for the exponent, but I can't figure out how.

Amber Lamps
01-22-2011, 10:58 AM
A friend on facebook posted this problem from her son's 6th grade math. I'm clearly an idiot, cause I can't figure it out.

If y*=3y-1, then what is 3*+5?

Seems to me that you have to solve for the y and also for the exponent, but I can't figure out how.

What does the "*" represent? Never mind I get it... you think you're dumb! Hahahaha

EpyonXero
01-22-2011, 12:10 PM
Is y* supposed to be y^x where x is a variable?

Trip
01-22-2011, 12:13 PM
Is y* supposed to be y^x where x is a variable?

yeah what was said above, the way you got it typed doesn't make sense and it's like his teacher made shit up. * is generally thought of as multiplication.

Amber Lamps
01-22-2011, 12:18 PM
yeah what was said above, the way you got it typed doesn't make sense and it's like his teacher made shit up. * is generally thought of as multiplication.

Yep....:lol: At first glance I was like WTF! I ASSume that * means "x" as in y to the x power.

Captain Morgan
01-22-2011, 12:21 PM
yeah what was said above, the way you got it typed doesn't make sense and it's like his teacher made shit up. * is generally thought of as multiplication.

Yep....:lol: At first glance I was like WTF! I ASSume that * means "x" as in y to the x power.

That's what I initially thought as well. but yeah, I also think it should be written as:

If y^x = 3y-1, then what is (3^x) + 5?

EpyonXero
01-22-2011, 12:28 PM
I dont think that was copied right, if solve for x you get a complex number.

Amber Lamps
01-22-2011, 12:29 PM
That's what I initially thought as well. but yeah, I also think it should be written as:

If y^x = 3y-1, then what is (3^x) + 5?

I keep coming up with 12.5...:lol:

y=2
x=2.5

Trip
01-22-2011, 12:38 PM
I dont think that was copied right, if solve for x you get a complex number.

yep, there is some math in there that is not 6th grade level, i think there is some missing info that the teacher gave. I don't remember logarithms that early.

EpyonXero
01-22-2011, 12:38 PM
I put it in Wolfram Alpha to see if I was missing something.

Trip
01-22-2011, 12:46 PM
This is what I got

y^x=3y-1

x= (ln(3y-1)/ln(y)) only if y > 1/3

z=3^x+5

z = (3y-1)^(ln(3)/ln(y))+5

So basically we have two equations and 3 unknowns.

Amber Lamps
01-22-2011, 12:46 PM
yep, there is some math in there that is not 6th grade level, i think there is some missing info that the teacher gave. I don't remember logarithms that early.

What's wrong with my answer?:lol:

Trip
01-22-2011, 12:49 PM
What's wrong with my answer?:lol:

because without more info there is infinite solutions.

EpyonXero
01-22-2011, 12:53 PM
Well the fact that we start with two variables, and only one complete equation means that you cant solve for both variables.

Amber Lamps
01-22-2011, 01:00 PM
because without more info there is infinite solutions.

Aw shucks...

I really want this to be

yx=3y-1 solve for 3x+5

y=1
x=2

solution=11
:lol:

DLIT
01-22-2011, 01:48 PM
Every now and again I like to look in these threads to make myself feel dumb. Success.

Amber Lamps
01-22-2011, 01:51 PM
Well the fact that we start with two variables, and only one complete equation means that you cant solve for both variables.

Yea I know... I still think that this is some kind of misprint or something...:wink:

Particle Man
01-22-2011, 01:54 PM
Every now and again I like to look in these threads to make myself feel dumb. Success.
Same here :lol

There's a reason I was an English major :lmao:

racedoll
01-22-2011, 02:23 PM
Sounds like you need to get more info from her before any of us can solve it.

Amber Lamps
01-22-2011, 02:26 PM
Sounds like you need to get more info from her before any of us can solve it.

Hey, I've solved it twice!:lol:

anthonyk
01-23-2011, 12:18 PM
Y'all are making this way too complicated, I think.

3*=3(3)-1 = 8

8+5 = 13

defector
01-23-2011, 12:50 PM
The answer is nipple. Duh.

Trip
01-23-2011, 01:28 PM
Y'all are making this way too complicated, I think.

3*=3(3)-1 = 8

8+5 = 13

Where are you getting 3* = 3^2

dReWpY
01-23-2011, 05:48 PM
the answer is 42

Captain Morgan
01-23-2011, 06:42 PM
Where are you getting 3* = 3^2

He was substituting 3 for y, implying that if y* = 3y-1, then 3*+5 should equal (3x3 -1) +5

Particle Man
01-23-2011, 07:04 PM
the answer is 42

The Ultimate Answer

anthonyk
01-24-2011, 10:46 AM
He was substituting 3 for y, implying that if y* = 3y-1, then 3*+5 should equal (3x3 -1) +5

Yup.

the chi
01-24-2011, 03:09 PM
I'm with Dlit.

Ugh.