View Full Version : Anyone here a math genius?
Captain Morgan
01-22-2011, 10:46 AM
A friend on facebook posted this problem from her son's 6th grade math. I'm clearly an idiot, cause I can't figure it out.
If y*=3y-1, then what is 3*+5?
Seems to me that you have to solve for the y and also for the exponent, but I can't figure out how.
Amber Lamps
01-22-2011, 10:58 AM
A friend on facebook posted this problem from her son's 6th grade math. I'm clearly an idiot, cause I can't figure it out.
If y*=3y-1, then what is 3*+5?
Seems to me that you have to solve for the y and also for the exponent, but I can't figure out how.
What does the "*" represent? Never mind I get it... you think you're dumb! Hahahaha
EpyonXero
01-22-2011, 12:10 PM
Is y* supposed to be y^x where x is a variable?
Is y* supposed to be y^x where x is a variable?
yeah what was said above, the way you got it typed doesn't make sense and it's like his teacher made shit up. * is generally thought of as multiplication.
Amber Lamps
01-22-2011, 12:18 PM
yeah what was said above, the way you got it typed doesn't make sense and it's like his teacher made shit up. * is generally thought of as multiplication.
Yep....:lol: At first glance I was like WTF! I ASSume that * means "x" as in y to the x power.
Captain Morgan
01-22-2011, 12:21 PM
yeah what was said above, the way you got it typed doesn't make sense and it's like his teacher made shit up. * is generally thought of as multiplication.
Yep....:lol: At first glance I was like WTF! I ASSume that * means "x" as in y to the x power.
That's what I initially thought as well. but yeah, I also think it should be written as:
If y^x = 3y-1, then what is (3^x) + 5?
EpyonXero
01-22-2011, 12:28 PM
I dont think that was copied right, if solve for x you get a complex number.
Amber Lamps
01-22-2011, 12:29 PM
That's what I initially thought as well. but yeah, I also think it should be written as:
If y^x = 3y-1, then what is (3^x) + 5?
I keep coming up with 12.5...:lol:
y=2
x=2.5
I dont think that was copied right, if solve for x you get a complex number.
yep, there is some math in there that is not 6th grade level, i think there is some missing info that the teacher gave. I don't remember logarithms that early.
EpyonXero
01-22-2011, 12:38 PM
I put it in Wolfram Alpha to see if I was missing something.
This is what I got
y^x=3y-1
x= (ln(3y-1)/ln(y)) only if y > 1/3
z=3^x+5
z = (3y-1)^(ln(3)/ln(y))+5
So basically we have two equations and 3 unknowns.
Amber Lamps
01-22-2011, 12:46 PM
yep, there is some math in there that is not 6th grade level, i think there is some missing info that the teacher gave. I don't remember logarithms that early.
What's wrong with my answer?:lol:
What's wrong with my answer?:lol:
because without more info there is infinite solutions.
EpyonXero
01-22-2011, 12:53 PM
Well the fact that we start with two variables, and only one complete equation means that you cant solve for both variables.
Amber Lamps
01-22-2011, 01:00 PM
because without more info there is infinite solutions.
Aw shucks...
I really want this to be
yx=3y-1 solve for 3x+5
y=1
x=2
solution=11
:lol:
Every now and again I like to look in these threads to make myself feel dumb. Success.
Amber Lamps
01-22-2011, 01:51 PM
Well the fact that we start with two variables, and only one complete equation means that you cant solve for both variables.
Yea I know... I still think that this is some kind of misprint or something...:wink:
Particle Man
01-22-2011, 01:54 PM
Every now and again I like to look in these threads to make myself feel dumb. Success.
Same here :lol
There's a reason I was an English major :lmao:
racedoll
01-22-2011, 02:23 PM
Sounds like you need to get more info from her before any of us can solve it.
Amber Lamps
01-22-2011, 02:26 PM
Sounds like you need to get more info from her before any of us can solve it.
Hey, I've solved it twice!:lol:
anthonyk
01-23-2011, 12:18 PM
Y'all are making this way too complicated, I think.
3*=3(3)-1 = 8
8+5 = 13
defector
01-23-2011, 12:50 PM
The answer is nipple. Duh.
Y'all are making this way too complicated, I think.
3*=3(3)-1 = 8
8+5 = 13
Where are you getting 3* = 3^2
dReWpY
01-23-2011, 05:48 PM
the answer is 42
Captain Morgan
01-23-2011, 06:42 PM
Where are you getting 3* = 3^2
He was substituting 3 for y, implying that if y* = 3y-1, then 3*+5 should equal (3x3 -1) +5
Particle Man
01-23-2011, 07:04 PM
the answer is 42
The Ultimate Answer
anthonyk
01-24-2011, 10:46 AM
He was substituting 3 for y, implying that if y* = 3y-1, then 3*+5 should equal (3x3 -1) +5
Yup.
the chi
01-24-2011, 03:09 PM
I'm with Dlit.
Ugh.
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