|
02-22-2011, 03:16 PM | #1 |
Semi-reformed Squid
Join Date: Nov 2008
Posts: 531
|
I must respectfully disagree. If it were in series, it wouldn't need to be nearly the size (power/wattage capacity), since it would only be passing a few milliamps. 'Load' resistors are way lower resistance (3~6 ohm) than a series resistor would need to be, and intended to wire 'across' (in parallel with) the LED to basically simulate the high current-draw of a normal bulb.
This one is 3-ohm, 50 watt: http://www.v-leds.com/BlinkerWarning...79822-1-3.html Here's a cool little calculator I found: http://www.hebeiltd.com.cn/?p=zz.led...lator#parallel Plug in 14V, 2V drop across led (lower than I thought), and 20ma for a single LED = 600-ohm, 1/2-watt (with safety-factor) required. For 6 similar LED's in parallel: 100-ohm, 3-watt Shit - I really need to get back to this mess I'm procrastinating on fixing @ the day-job! Last edited by Kerry_129; 02-22-2011 at 03:18 PM.. |
Bookmarks |
|
|